a) Two 66 g ice cubes are dropped into 232 g of water in athermally insulated co

Question

a) Two 66 g ice cubes are dropped into 232 g of water in athermally insulated container. If the water is initially at25°C, and the ice comes directly from a freezer at -15°C,what is the final temperature at thermal equilibtrium? (Neglect theheat capacity of the glass.)
b) What is the final temperature if only one ice cube isused?
a) Two 66 g ice cubes are dropped into 232 g of water in athermally insulated container. If the water is initially at25°C, and the ice comes directly from a freezer at -15°C,what is the final temperature at thermal equilibtrium? (Neglect theheat capacity of the glass.)
b) What is the final temperature if only one ice cube isused?

Explanation / Answer

We have:
          specific heat of ice=0.5            specificheat of water ==1 L of ice=80 Heat gained =2*66*1/2*15+2*66*80+132(t-0) (1) Heat lost=1*232*(25-t) (2) From (1) and (2), we have: 2*66*1/2*15+2*66*80+132(t-0) = 1*232*(25-t) => t= -15.80 0c The final temperature if only one ice cube is used is:         66*1/2*15+66*80+66t=232(25-t) => t=0.250c => t= -15.80 0c The final temperature if only one ice cube is used is:         66*1/2*15+66*80+66t=232(25-t) => t=0.250c

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