Light of wavelength 625 nm shines through a single slit ofwidth 0.32 mm and form

Question

Light of wavelength 625 nm shines through a single slit ofwidth 0.32 mm and forms a diffraction pattern on a flat screenlocated 8.0 m away. Determine the distance between the middle ofthe central bright fringe and the first dark fringe.

a. 1.56 cm
b. 0.516 cm
c. 0.156 cm
d. 6.51 cm
e. 5.16 cm Light of wavelength 625 nm shines through a single slit ofwidth 0.32 mm and forms a diffraction pattern on a flat screenlocated 8.0 m away. Determine the distance between the middle ofthe central bright fringe and the first dark fringe. 1.56 cm 0.516 cm 0.156 cm 6.51 cm 5.16 cm

Explanation / Answer

Light of wavelength = 625 nm
                                = 625 * 10 ^ -9 m single slit of width d = 0.32 mm                                = 0.32 * 10 ^ -3 m distance of the screen from slit   D = 8.0m condition for 1 st dark fringe is d sin = at small angles   sin ~ tan = y/ D So, d ( y / D ) = from this the distance between the middle of the centralbright fringe and the first dark fringe y = D / d                                                                                                                                              = 1.5625* 10 ^ -2 m                                                                                                                                              = 1.5625 cm

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