A beam of light is incident from air on the surface of a liquid. Ifthe angle of

Question

A beam of light is incident from air on the surface of a liquid. Ifthe angle of incidence is 35.0°and the angle of refraction is 24.0°, find the critical angle for the liquidwhen surrounded by air.

Explanation / Answer

In the first case, the light goes from a lower --> higher indexof refraction (not possible for critical angle in thiscase). First find the index of refraction: sin35.0 = N sin24.0 N = sin35.0 / sin24.0 = 1.41 Now the light goes from the liquid to air, so there is criticalangle possible N sin = 1    by def'n of refraction atcritical angle sin = 1 / N = sin-1(1/1.41) = 45.2o

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