Pushing on the pump of a soap dispenser compresses a smallspring. When the sprin

Question

Pushing on the pump of a soap dispenser compresses a smallspring. When the spring is compressed 0.49 cm, its potential energyis 0.0025 J.          (a) Whatis the force constant of thespring?        kN/m?             (b)What compression is required for the spring potential energy toequal 0.0083 J?        cm? Pushing on the pump of a soap dispenser compresses a smallspring. When the spring is compressed 0.49 cm, its potential energyis 0.0025 J.          (a) Whatis the force constant of thespring?        kN/m?             (b)What compression is required for the spring potential energy toequal 0.0083 J?        cm?

Explanation / Answer

compression x = 0.49 cm                       = 0.0049 m potential energy U = 0.0025 J we know U = ( 1/ 2) k x ^ 2 from this force constant k = 2U / x ^ 2                                        = 208.24 N / m                                        = 0.20824 kN / m (b). potential energy U ' = 0.0083 J                  ( 1/ 2) k x ' ^ 2 = 0.0083 J from this x ' = [ 2 * 0.0083 / 208.24 ]                    =0.008928 m                   = 0.8928 cm

Related Questions

Navigate

• Browse (All)
• Browse P
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.