a) A ray of light 480nm wavelength in air (n=1) makes an angleof incidence, 30.0
ID: 1757132 • Letter: A
Question
a) A ray of light 480nm wavelength in air (n=1) makes an angleof incidence, 30.0 degrees, as it enters clear ice (n=1.309), Findi) the angle of refraction, ii) the speed of light in the ice andiii) thewavelength of light in ice. (speed of light in air=3x10^8) b) The critical angle for total internal reflection at diamondair interface in 41 Do. What is the speed of light in thediamond? a) A ray of light 480nm wavelength in air (n=1) makes an angleof incidence, 30.0 degrees, as it enters clear ice (n=1.309), Findi) the angle of refraction, ii) the speed of light in the ice andiii) thewavelength of light in ice. (speed of light in air=3x10^8) b) The critical angle for total internal reflection at diamondair interface in 41 Do. What is the speed of light in thediamond?Explanation / Answer
wavelength = 480 * 10 ^ -9 m incident angle i = 30 degrees index of refraction of ice n = 1.309 (i). from snell's law sin i / sin r = n sin r = sin i / n = 0.3819 angle of refraction r = 22.45 degrees (ii) .speed of light in ice v = c / n = ( 3 * 10 ^ 8 ) / 1.309 = 2.291 * 10 ^ 8 m / s ( iii) . wavelength of light in ice '= / n = 366.69 nm (b) . critical angle C = 41 degrees we know sin C = 1/ n ' from this index of refraction of diamond n ' = 1 / sinC = 1.5242 So, speed of light in diamond v ' = c / n ' = ( 3 * 10 ^ 8 m / s ) / 1.5242 = 1.968 * 10 ^ 8 m / sRelated Questions
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