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You identify a locus t has three alleles A ,A and A and you want to check to det

ID: 175687 • Letter: Y

Question

You identify a locus t has three alleles A ,A and A and you want to check to determine if they are in Hardy-Weinberg equilibrium. You determine the genotype a group of genetics students and get the following distribution. Fill in the blanks to four decimal points and use the Chi-square test to determine if they are in HWE. Expected Number of Expected Genotype Genotype Frequency ndividuals Genotype Number A A 418 A A 721 A A 963 1024 A 1734 AA 1140 A Allele Frequency A Allele Frequency A Allele Frequency How many degrees of freedom will you use? What is the critical chi-square value with an alpha of 0.05? What is the chi-squared value for these data? Is this locus in Hardy-Weinberg Equilibrium?

Explanation / Answer

A1 = p

A2 = q

A3 = r

Given, A1A1 = 418 = 0.4 = 2p

p = 0.2

Given, A2A2 = 721 = 0.7 = 2q

q = 0.35

Given, A3A3 = 963 = 0.9 = 2r

r = 0.45

A1A1

418

(0.2+0.2) = 0.4

(0.2+0.2)*100 = 400

A2A2

721

(0.35+0.35) = 0.7

(0.35+0.35)*100 = 700

A3A3

963

(0.45+0.45) = 0.9

(0.45+0.45)*100 = 900

A1A2

1024

2*(0.2+0.35)=1.0

2*(0.2+0.35)*100 = 1000

A2A3

1734

2*(0.35+0.45)= 1.6

2*(0.35+0.45)*100 = 1600

A1A3

1140

2*(0.2+0.45) = 1.3

2*(0.2+0.45)*100 = 1300

A1 allele frequency = 0.2

A2 allele frequency = 0.35

A1 allele frequency = 0.45

Kindly ask remaining questions as separate post!!!

A1A1

418

(0.2+0.2) = 0.4

(0.2+0.2)*100 = 400

A2A2

721

(0.35+0.35) = 0.7

(0.35+0.35)*100 = 700

A3A3

963

(0.45+0.45) = 0.9

(0.45+0.45)*100 = 900

A1A2

1024

2*(0.2+0.35)=1.0

2*(0.2+0.35)*100 = 1000

A2A3

1734

2*(0.35+0.45)= 1.6

2*(0.35+0.45)*100 = 1600

A1A3

1140

2*(0.2+0.45) = 1.3

2*(0.2+0.45)*100 = 1300

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