Greetings all, I am having trouble understanding a two part question inphysics.
ID: 1756812 • Letter: G
Question
Greetings all, I am having trouble understanding a two part question inphysics. Part A asks: If the distance between a point charge and aninfinitely large charged plate is increased by a factor of 2, thenew force on the point charge will: Choice A: decrease by a factor of 4 B: dec by 2 C. Remain the same D. increase by a factor of 2 The correct answer is C, remain the same. I don't understandwhy this is so? The solution states that the electric field abovean infinitely large elecgtric plate remains constant with distance.THe field lines would remain at equal distance from one another,the electric field wold remain constant? ^^ I don't understand this explanation or question atall. Part B: Two particles are held in equilibrium by thegravitational force and electrostatic forces between them. ParticleA has mass Ma and chrage Qa. Particle B has mass Mb and chrage Qb.The distance between the chrages is d. Which of the follwoingchanges will cause the charges to accelerate toward oneanother? Choice A: Ma is doubled and Mb is doubled B: Ma is doubled and Mb is halved. C: Qa is doubled and Qb is doubled. D: d is doubled. The correct answer is A; The solution states that doublingboth masses will increase the attractive gravitational forces.Choice C is wrong bc doubling both charges wll increase repulsiveelectrical force. And choice B and D do not change the forces atall. ^^ I don't understand this explanation. I know that the forceof gravitiy=mg. For someone who can simplify this into easy terms, I willrate a lifesaver! Thanks. Greetings all, I am having trouble understanding a two part question inphysics. Part A asks: If the distance between a point charge and aninfinitely large charged plate is increased by a factor of 2, thenew force on the point charge will: Choice A: decrease by a factor of 4 B: dec by 2 C. Remain the same D. increase by a factor of 2 The correct answer is C, remain the same. I don't understandwhy this is so? The solution states that the electric field abovean infinitely large elecgtric plate remains constant with distance.THe field lines would remain at equal distance from one another,the electric field wold remain constant? ^^ I don't understand this explanation or question atall. Part B: Two particles are held in equilibrium by thegravitational force and electrostatic forces between them. ParticleA has mass Ma and chrage Qa. Particle B has mass Mb and chrage Qb.The distance between the chrages is d. Which of the follwoingchanges will cause the charges to accelerate toward oneanother? Choice A: Ma is doubled and Mb is doubled B: Ma is doubled and Mb is halved. C: Qa is doubled and Qb is doubled. D: d is doubled. The correct answer is A; The solution states that doublingboth masses will increase the attractive gravitational forces.Choice C is wrong bc doubling both charges wll increase repulsiveelectrical force. And choice B and D do not change the forces atall. ^^ I don't understand this explanation. I know that the forceof gravitiy=mg. For someone who can simplify this into easy terms, I willrate a lifesaver! Thanks.Explanation / Answer
Given : As we know that Force ( F ) = k q1 q2 /r2 one of them is a infinite large charged plate. That tells you the force between two point charges--notrelevant here. Instead, think of the field produced by the chargedplate and the force that field exerts on the point charge That means that the number is so large that there willbe no difference in the force exerted on the point charge no matterit's distance from the other. The electric field above aninfinitely large electric plate remains constant withdistance I hope this information helps youone of them is a infinite large charged plate. That tells you the force between two point charges--notrelevant here. Instead, think of the field produced by the chargedplate and the force that field exerts on the point charge That means that the number is so large that there willbe no difference in the force exerted on the point charge no matterit's distance from the other. The electric field above aninfinitely large electric plate remains constant withdistance I hope this information helps you
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.