A medical researcher wishes to compare the tissue damageproduced by slow neutron
ID: 1756764 • Letter: A
Question
A medical researcher wishes to compare the tissue damageproduced by slow neutrons, which have a relative biologicaleffectiveness (RBE) of 2.2, to that produced by fast neutrons withan RBE of 8.8. For the slow neutrons, the absorbed dose is 560 rd.What absorbed dose (in rd) of fast neutrons will produce the samebiologically equivalent dose (in rem) as that for the slowneutrons?a. 29 rd
b. 2240 rd
c. 310 rd
d. 140 rd
e. 560 rd A medical researcher wishes to compare the tissue damageproduced by slow neutrons, which have a relative biologicaleffectiveness (RBE) of 2.2, to that produced by fast neutrons withan RBE of 8.8. For the slow neutrons, the absorbed dose is 560 rd.What absorbed dose (in rd) of fast neutrons will produce the samebiologically equivalent dose (in rem) as that for the slowneutrons? 29 rd 2240 rd 310 rd 140 rd 560 rd
Explanation / Answer
Given RBE of slow neutrons = 2.2 RBE of fas5t neutrons = 8.8 absorbed dose = 560 rad For slow neutrons dose in rem = ( dose in rad ) x (RBE ) = (560 )(2.2 ) = 1232 rad absorbed dose of fast neutrons dose in rad = dose in rem / RBE = 1232 / 8.8 = 140 rad Given RBE of slow neutrons = 2.2 RBE of fas5t neutrons = 8.8 absorbed dose = 560 rad For slow neutrons dose in rem = ( dose in rad ) x (RBE ) = (560 )(2.2 ) = 1232 rad absorbed dose of fast neutrons dose in rad = dose in rem / RBE = 1232 / 8.8 = 140 rad Answer is ' d 'Related Questions
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