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How far away does the image appear toJoe? Express your answer in meters, tothree

ID: 1756641 • Letter: H

Question

How far away does the image appear toJoe? Express your answer in meters, tothree significant figures or as a fraction. How far away does the image appear toJoe? Express your answer in meters, tothree significant figures or as a fraction. How far away does the image appear toJoe? Express your answer in meters, tothree significant figures or as a fraction. How far away does the image appear toJoe? Express your answer in meters, tothree significant figures or as a fraction. How far away does the image appear toJoe? Express your answer in meters, tothree significant figures or as a fraction. How far away does the image appear toJoe? Express your answer in meters, tothree significant figures or as a fraction. How far away does the image appear toJoe? Express your answer in meters, tothree significant figures or as a fraction. How far away does the image appear toJoe? Express your answer in meters, tothree significant figures or as a fraction. How far away does the image appear toJoe? Express your answer in meters, tothree significant figures or as a fraction. How far away does the image appear toJoe? Express your answer in meters, tothree significant figures or as a fraction. How far away does the image appear toJoe? Express your answer in meters, tothree significant figures or as a fraction. How far away does the image appear toJoe? Express your answer in meters, tothree significant figures or as a fraction. How far away does the image appear toJoe? Express your answer in meters, tothree significant figures or as a fraction. How far away does the image appear toJoe? Express your answer in meters, tothree significant figures or as a fraction.

Explanation / Answer

radius of curvature=R=30 so focal length=R/2=15m u=5m from the mirror equation we have 1/v=1/f+1/u=1/15+1/5=4/15 so v=15/4=3.75m How far away does the image appear to Joe? v=3.75m from the optic center. but from joe the image distance =5+3.75=8.75m

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