1)An electric heater operating at full power draws a current of 13.1 A from a 12
ID: 1756225 • Letter: 1
Question
1)An electric heater operating at full power draws a current of 13.1 A from a 123 V circuit. What is the resistance of the heater? Answer in unitsof .2)Assuming constant R, how much current should the heater draw in order to dissipate 1130 W? Answer in units of A.
for part 1 i got 9.4 by dividing 123 V by 13.1 A for part two would I would set up the equationI=(.5*1130W*9.4)^1/2 is this correct? 1)An electric heater operating at full power draws a current of 13.1 A from a 123 V circuit. What is the resistance of the heater? Answer in unitsof .
2)Assuming constant R, how much current should the heater draw in order to dissipate 1130 W? Answer in units of A.
for part 1 i got 9.4 by dividing 123 V by 13.1 A for part two would I would set up the equationI=(.5*1130W*9.4)^1/2 is this correct?
Explanation / Answer
1) R = V/I = 123V/13.1A = 9.4 2) since R is constant, we have: P = IV = I2 R ->I = (P/R) = (1130W/9.4) =10.96A .Related Questions
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