A ship travels at 30 km/h 30 degrees east of north, then 20km/h 60 degrees south

Question

A ship travels at 30 km/h 30 degrees east of north, then 20km/h 60 degrees south of west for 17 hours. What is the totaldisplacement? My approach: I'm thinking you'resupposed to use kinematics to find the distance of each segment ittravels. Then use pythagoras to calculate the total distance? Isthat right? A ship travels at 30 km/h 30 degrees east of north, then 20km/h 60 degrees south of west for 17 hours. What is the totaldisplacement? My approach: I'm thinking you'resupposed to use kinematics to find the distance of each segment ittravels. Then use pythagoras to calculate the total distance? Isthat right?

Explanation / Answer

let the unit vector in east direction be i    and in north direction be  j then Given V = 30 sin 30 i + 30 cos30 j               = 15 i + 25.98 j            V ' = - 20 cos 60 i - 20 sin 60 j                 = -10 i - 17.32 j So, resultanr velocity   V " = V + V '                                         = 5 i + 8.659 j Magnitude of V " = [ 5 ^ 2 + 8.659 ^ 2 ]                            ~10 km / h time t = 17 h So, total displacement   S = v t                                       = 170 km

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