A spring, of negligible mass and which obeys Hooke\'s Law,supports a mass M on a

Question

A spring, of negligible mass and which obeys Hooke's Law,supports a mass M on an incline which has negligible friction. Thefigure below shows the system with mass M in its equilibriumposition. The spring is attached to a fixed support at P. Thespring in its relaxed state is also illustrated.

Mass M has a value of 275 g. Calculate k, thespring constant.
The mass oscillateswhen given a small displacement from its equilibrium position alongthe incline. Calculate the oscillation frequency.

Here's the image http://i32.photobucket.com/albums/d2/NikkiNik88/plot.png
I did: a= (-k/m)*x I used the mass given, a=g,and x =0.3m and I got 8.998 but that's wrong. Pleaehelp
A spring, of negligible mass and which obeys Hooke's Law,supports a mass M on an incline which has negligible friction. Thefigure below shows the system with mass M in its equilibriumposition. The spring is attached to a fixed support at P. Thespring in its relaxed state is also illustrated.

Mass M has a value of 275 g. Calculate k, thespring constant.
The mass oscillateswhen given a small displacement from its equilibrium position alongthe incline. Calculate the oscillation frequency.

Here's the image http://i32.photobucket.com/albums/d2/NikkiNik88/plot.png
I did: a= (-k/m)*x I used the mass given, a=g,and x =0.3m and I got 8.998 but that's wrong. Pleaehelp

Explanation / Answer

given mass = m = 275g = 0.275kg      displacement = x = 0.3m spring constant k = F/x = mg /x plug valuek = ----- time period = T = 2m/k plug values T = ------s    oscillting frequency = n = 1/T = ------hz

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