Two blocks attached by a string slide down a 19? incline.The lower block has a m
ID: 1754600 • Letter: T
Question
Two blocks attached by a string slide down a 19? incline.The lower block has a mass of 0.25 kg and a coefficient of kinetic friction of 0.1. Theupper block has a mass of 0.7 kg and a coefficient of kinetic friction of 0.5.Find the magnitude of the acceleration of the blocks. Theacceleration of gravity is 9.81 m/s2 . Answer in units ofm/s2.
Find the tension in the string. Answer in units ofN.
Two blocks attached by a string slide down a 19? incline.The lower block has a mass of 0.25 kg and a coefficient of kinetic friction of 0.1. Theupper block has a mass of 0.7 kg and a coefficient of kinetic friction of 0.5.
Find the magnitude of the acceleration of the blocks. Theacceleration of gravity is 9.81 m/s2 . Answer in units ofm/s2.
Two blocks attached by a string slide down a 19? incline.The lower block has a mass of 0.25 kg and a coefficient of kinetic friction of 0.1. Theupper block has a mass of 0.7 kg and a coefficient of kinetic friction of 0.5.
Find the magnitude of the acceleration of the blocks. Theacceleration of gravity is 9.81 m/s2 . Answer in units ofm/s2.
Find the tension in the string. Answer in units ofN.
Explanation / Answer
Consider the forces acting on both blocks along the incline:
.
component of mg on block 1 - friction on block1 + comp of mg on block 2 - friction onblock 2 = total mass * acc
.
m1 g sin19 - u1 m1 gcos19 + m2 g sin19 - u2 m2 gcos19 = (m1 + m2) a
.
plug in numbers and solve for a, the acceleration:
.
0.25 * 9.8 * sin19 - 0.1 * 0.25 * 9.8 *cos19 + 0.7 * 9.8 * sin19 - 0.5 * 0.7*9.8*cos19 =(0.25+0.7) a
.
-0.44373 = 0.95 a
.
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