Hello, if someone could please help me with a problem, I wouldbe most appreciati

Question

Hello, if someone could please help me with a problem, I wouldbe most appreciative.   Thank you in advance is you areable!!   :-) A pendulum clock can be approximated as a simple pendulum oflength 1.00 m and keeps accurate time at a location where g = 9.83m/s^2.   In location where g = 9.78 m/s^2, what must bethe new length of the pendulum, such that the clock continues tokeep accurate time (that is, its period remains the same). Thanks again, everyone! Hello, if someone could please help me with a problem, I wouldbe most appreciative.   Thank you in advance is you areable!!   :-) A pendulum clock can be approximated as a simple pendulum oflength 1.00 m and keeps accurate time at a location where g = 9.83m/s^2.   In location where g = 9.78 m/s^2, what must bethe new length of the pendulum, such that the clock continues tokeep accurate time (that is, its period remains the same). Thanks again, everyone!

Explanation / Answer

We know , time period of a pendulum is directly proportional to(l/g So when time period are equal , L1/L2 = g1/g2 Putting the values 1 subscript is for initial condition , 1.00 / L2 = 9.83 / 9.78 L2= 0.995 m

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