Problem: A 2.2 kg block of ice initially at atemperature of -20c is immersed in
ID: 1753693 • Letter: P
Question
Problem:A 2.2 kg block of ice initially at atemperature of -20c is immersed in a very large amount of liquidnitrogen (LN) at a temperature of -196c, and the nitrogen andH2O are allowed to come to thermal equilibrium [Tbp(N2)=-196C]Create a particular model of this process and use it to determinehow much LN is converted to gas vapor My thoughts: There are very large amount ofliquid nitrogen so implies that there weill still beLN left when the two come tothermal equilibrium. Question: We did not know what the final tempertaure that borht of themwill reach and we did not know the mass of LN. How do wecalcualted how much Ln is converted to vapor? H2Oare allowed tocome to thermal equilibrium will that affect the ice and Ln'sequilibrium? Problem:
A 2.2 kg block of ice initially at atemperature of -20c is immersed in a very large amount of liquidnitrogen (LN) at a temperature of -196c, and the nitrogen andH2O are allowed to come to thermal equilibrium [Tbp(N2)=-196C]Create a particular model of this process and use it to determinehow much LN is converted to gas vapor My thoughts: There are very large amount ofliquid nitrogen so implies that there weill still beLN left when the two come tothermal equilibrium. Question: We did not know what the final tempertaure that borht of themwill reach and we did not know the mass of LN. How do wecalcualted how much Ln is converted to vapor? H2Oare allowed tocome to thermal equilibrium will that affect the ice and Ln'sequilibrium?
Explanation / Answer
Let M be the mass of ice , and m be the mass of liquidnitrogen heat gained by liquid nitrogen =heat lost by ice heat gained by liquidnitrogen in two ways, in rising its temparature to boling point in liquidstate + heat gained in converting to vapour state Qnet = Q +Q' =mST + mL T = -195-(- 196 C) m = mass of liquid nitrogen S = specific heat of liquid nitrogen T = 1C. heat lost by ice Qnet = MS'T' T' = -Tf M = mass of ice S' = specific heat of ice T = final temparature Qnet = MS'T' = mST +mL . from the abv relation we can solve for finaltemparature "-Tf "Related Questions
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