a 1.00 kg block is placed on an inclined plane that makes an angle of 45 degrees

Question

a 1.00 kg block is placed on an inclined plane that makes an angle of 45 degrees with the horizontal, the block is also attached to a 0.200 kg counter weight by a cord that passes over a frictionless and massesless pulley that is located atthe top of the incline. assume that th coefficent of kinetic friction between the block and the incline is 0.24 and the coefficent and the coefficent of static friction is 0.38 A) Show that the counterweight will not prevent the block from sliding down the incline. B) at waht rate will the bock accelerate downward along the incline?

Explanation / Answer

the force acting on the block down the incline               F = mg sin     = angle of incline withhorizantal      m = mass of the block frictional force which opposing the motion of theblock         Fs =(+')mg cos and the force due to the counter mass hanging at the top of pully is         Fp = mg       net force on the slidingblock             Fnet=  F - Fs-Fp Fnet > 0 if and only if we consider Fp due to themass. and final acceleration of the block          a = Fnet /m m = mass of the block .

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