A square loop of wire with 2.00 m sides is perpendicular to auniform magnetic fi

Question

A square loop of wire with 2.00 m sides is perpendicular to auniform magnetic field that points into the paper. Themagnitude of the field varies with time according to
B = 0.042 - 0.870 t with B in Teslas and t in seconds. a) What is the average EMFin the circuit in the interval of time between t = 0s and t = 2 s?b) What is the direction of the current through the resistor? A square loop of wire with 2.00 m sides is perpendicular to auniform magnetic field that points into the paper. Themagnitude of the field varies with time according to
B = 0.042 - 0.870 t with B in Teslas and t in seconds. a) What is the average EMFin the circuit in the interval of time between t = 0s and t = 2 s?b) What is the direction of the current through the resistor?

Explanation / Answer

         Given thatthe length of each side is L = 2.00 m          The magneticfield is B = 0.042-0.870t -------------------------------------------------------------------------    The induced emf is = -d /dt                                    =-d(B.A)/dt                                    =-AdB/dt                                    =-4m2*(-0.870)T                                    = 3.48V The direction of current is counterclock wise viewedfrom above.        

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