I did this equation another way and got a differentanswer could you double check

Question

I did this equation another way and got a differentanswer could you double check to see which is correct. Inquiry into Physics chapter 5 4P A copper vat is 10m long at room temp (20degrees). how muchlonger is it when it contains boiling water at 1 atmpressure? 100degrees - 20degrees = 80degrees (17 x 10 ^-6/ degrees C)X 10M X 80 degrees= 0.0136m I did this equation another way and got a differentanswer could you double check to see which is correct. Inquiry into Physics chapter 5 4P A copper vat is 10m long at room temp (20degrees). how muchlonger is it when it contains boiling water at 1 atmpressure? 100degrees - 20degrees = 80degrees (17 x 10 ^-6/ degrees C)X 10M X 80 degrees= 0.0136m

Explanation / Answer

Actually, what you have calculated is the change in length ofthe copper vat. The formula says l (t) = l0 (1 +*) Now, since you have calculated l by using l0**, just add this with the original value oflength l0 , So, the final length of the copper vat would be 10 + 0.0136which is 10.0136 m.

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