A person stands on a scale in an elevator. The maximum andminimum scale readings

Question

A person stands on a scale in an elevator. The maximum andminimum scale readings are 764.5 N and 346.6 N, respectively. Theacceleration of gravity is 9.8 m/s2. Assume themagnitude of the acceleration is the same during starting andstopping, and determine the weight of the person. Answer in unitsof N. b.) Determine the person's mass. Answer in units of kg. c.) Determine the acceleration of the elevator. Answer inunits of m/s2. A person stands on a scale in an elevator. The maximum andminimum scale readings are 764.5 N and 346.6 N, respectively. Theacceleration of gravity is 9.8 m/s2. Assume themagnitude of the acceleration is the same during starting andstopping, and determine the weight of the person. Answer in unitsof N. b.) Determine the person's mass. Answer in units of kg. c.) Determine the acceleration of the elevator. Answer inunits of m/s2.

Explanation / Answer

The physics is Newton's 2nd Law of motion.   Net force = m a going UP:          N - m g = ma ,   where N is the upward normal force that the scale exerts on theperson. going DOWN:    N - m g = - m a plug in the two given normal forces to get: 764.5 - m g = m a 346.6 - m g = - m a Now, add these two equations to eliminate the ma terms on theright. 1111.1 - 2 m g = 0    solve for m toget    56.69 kg   Thus, the weight of theperson is mg = 555.56 N. plug in value of m just found into either of the two eqns tofind   a = 3.69 m/s2

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