On step 4 in this solution when you are simplifingequation: Force of friction-Fo

Question

On step 4 in this solution when you are simplifingequation:
Force of friction-Force applied = mass1acceleration1 shouldn't you get Force of friction -force applied =acceleration1                                          mass1 If not, how do you get acceleration 1 = Force applied                                                              mass1- Force of friction On step 4 in this solution when you are simplifingequation:
Force of friction-Force applied = mass1acceleration1 shouldn't you get Force of friction -force applied =acceleration1                                          mass1 If not, how do you get acceleration 1 = Force applied                                                              mass1- Force of friction                                                              mass1- Force of friction

Explanation / Answer

I should have been clearer. A block of mass m=2.00kg rests on the left edge of a block oflength L=3.00 m and mass M=8.00kg. The coefficent of the kineticfriction between the two blocks is k=0.300, and the surfaceon which the 8.00kg block rests is frictionless. A constanthorizontal force of magnitude F=12.0N is applied to the 2.00kgblock, setting it in motion. How long will it take before this block makes it to the rightside of the 8.00kg block?(Hint: Both blocks are set in motion whenthe force vector F is applied.) How far does the 8.00kg block move in the process?

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