A negative electron is traveling in the negative x direction with velocity v = -

Question

A negative electron is traveling in the negative xdirection with velocity v = -vi.Suddenly, the electron experiences a uniform external electricfield (i.e. the field was not previously present), perpendicular tothe electron's initial motion, E = Ei.the electric field remains only for 1s and then vanishes. Inwhat direction will the electron be traveling after the fieldvanishes?
1. Identify and list known values. Define and newvariables/quantities you use.
2. Find the force on, and thereby the acceleration of, the electrondue to the electric field.
3. Using the equations of motion, find the velocity of the electronin vector form.
4. Determine the angle from the x-axis of the velocity using itsvector components.

Explain it as well as you can please!

Explanation / Answer

x direction with velocity v =-vi. it was given the electron was intially moving along -xdirection let intial velocity along x- axis is                 Vi =Vx when a magnetic field was applied in perpendicular directionpointing +y axis perpendicular to the electron's initial motion, E= Ej perpendicular to the electron's initial motion, E= Ej since the electron will experience a electricforce towards -y axis it undergoes a displacementalong negative y axis .         force on theelectron in -y direction            F = qE          accelerationalong -y axis                   a = F / me      if the electron acclerates for a timeinterval of t sec , displacement along -y axis           S =at^2 / 2           and final velocity along -y axis              vy = at initally the electron pocesses velocity along alongnegative x axis , and final velocity includes velocity along -yaxis too. final velocity V = [(-Vx)^2 +(-Vy)^2] angle made by the velocity vector V with x-axis                   tan = Vy / Vx                                  

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