1) A parallel beam of light is sent through an aquarium (i.e.a rectangular box w

Question

1) A parallel beam of light is sent through an aquarium (i.e.a rectangular box with glass sides, filled with water). A conves glass lens is held in water. Compared to thebehaviour of the same lens in air, will the lens in water focus thebeam: a) closer to the lens than in air; b) at the same position as in air; c) further from the lens than in air? (Hint: The magnitude of the refractive index of water isbetween the magnitudes of the refractive indices of the lensmaterial and air) -- 2) The water in the aquarium is replaced by a transparentliquid with refractive index with greater than that of the lens.Will the lens now be a convergent or a divergent lens?Explain. Thanks. 1) A parallel beam of light is sent through an aquarium (i.e.a rectangular box with glass sides, filled with water). A conves glass lens is held in water. Compared to thebehaviour of the same lens in air, will the lens in water focus thebeam: a) closer to the lens than in air; b) at the same position as in air; c) further from the lens than in air? (Hint: The magnitude of the refractive index of water isbetween the magnitudes of the refractive indices of the lensmaterial and air) -- 2) The water in the aquarium is replaced by a transparentliquid with refractive index with greater than that of the lens.Will the lens now be a convergent or a divergent lens?Explain. Thanks.

Explanation / Answer

) A parallel beam of light is sent through an aquarium (i.e. arectangular box with glass sides, filled with water). A convex glass lens is held in water. Compared to the behaviorof the same lens in air, will the lens in water focus thebeam: a) closer to the lens than in air; b) at the same position as in air; c) further from the lens than in air? (Hint: The magnitude of the refractive index of water isbetween the magnitudes of the refractive indices of the lensmaterial and air)
when the lens is immersed in water
1/f=(/w-1)[1/R1-1/R2]
from this formula when lens is immersed in water whoserefractive index is less than the refractive index of theglass the
2) The water in the aquarium is replaced by a transparentliquid with refractive index with greater than that of the lens.Will the lens now be a convergent or a divergent lens? Explain.
from the above explanation
focal length will become negative and hence lens will behave asdivergent lens.

Thanks.

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