I am not enjoying these problems. Could someone please helpme with this problem
ID: 1752166 • Letter: I
Question
I am not enjoying these problems. Could someone please helpme with this problem and break it down it to steps for me so I cansee what is taking place.The coefficient of static friction between a block and a horizontalfloor is 0.75, while the coefficient ofkinetic friction is 0.15. The mass of theblock is 8.0 kg. A horizontal force isapplied to the block and slowly increased. (a) What is the value of the applied horizontalforce at the instant that the block starts to slide?
1 N
(b) What is the net force on the block after it starts toslide?
2 N
Thank you!
(a) What is the value of the applied horizontalforce at the instant that the block starts to slide?
1 N
(b) What is the net force on the block after it starts toslide?
2 N
Thank you!
Explanation / Answer
part a: F - fmax = 0 F = fmax = sN = smg =(.75)(8.0)(9.8) = 58.8 N Part b F = F - fk = F - kN = F -kmg = (58.8) - (.15)(8)(9.8) = 47.04 N
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