Starting from rest, a 11.42-cm-diameter compactdisk takes 3.4 s to reach its ope

Question

Starting from rest, a 11.42-cm-diameter compactdisk takes 3.4 s to reach its operating angular velocity of 2385rpm. Assume that the angular acceleration is constant. Thedisk’s moment of inertia is 1.00×10-5kg·m2. How much torque is applied to thedisk?

How many revolutions does it make before reaching fullspeed?
Starting from rest, a 11.42-cm-diameter compactdisk takes 3.4 s to reach its operating angular velocity of 2385rpm. Assume that the angular acceleration is constant. Thedisk’s moment of inertia is 1.00×10-5kg·m2. How much torque is applied to thedisk?

How many revolutions does it make before reaching fullspeed?

Explanation / Answer

Moment of inertia (I) of the disk = 1.00×10-5kg·m2 Initial angular speed (o) of the disk =0 Final angular speed () of the desk = 2385 rpm                                                       =(2385)(2/60)rad/s Time interval (t) = 3.4s Now angular acceleration () of the desk is                   = ( - o) / t Now torque acting on the desk is                               = I Do the calculation work.

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