Susan horizontally accelerates a beam of protons, intially atrest, between the p

Question

Susan horizontally accelerates a beam of protons, intially atrest, between the plates of parallel-plate capacitor, thepotential difference (v) between the plates is 1000Vand the plate separation is 1.50 cm. the particle then enters aregion where a uniform magnetic field, B = 0.913 T(directed out thepage). To detect the particle, a sensor is located directly belowthe point where the particle enters the field. Determine the magnetic force vector in component form exertedon the particle immediately after it enters the magneticfield? In order to detect the exiting particle at what distance belowthe particle enterance point does the sensor need to beplaced? Next, a beam of alpha particles is then accelerated (same asdelta v as above) and fired into the magnetic field. to whatmagnitude should the magnetic field be is adjusted to so thatthe particles will be detected by the sensor? the mass of alphaparticl is 4.64*10^-27kg and the charge is 2e.

Explanation / Answer

The velocity of the particle just as it enter themagnetic field is                  v = E / B                     = V / B*d                     = 1000 V / 0.913 T * 0.015m                     = 7.30 x 104 m/s Magnetic force F = qvB                           = 2*1.602 x 10-19C * 7.30 x 104m/s * 0.913 T                           =21.36 x 10-15 N

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