Two masses are suspended by cord that passes over a pulleywith negligible mass.

Question

Two masses are suspended by cord that passes over a pulleywith negligible mass. The cord also has negligible mass. One of themasses, m1, has a mass of 6.0 kg and the other mass, m2, has a massof 4.0 kg. The force of the cord attached to m1 is, Tension ? Two masses are suspended by cord that passes over a pulleywith negligible mass. The cord also has negligible mass. One of themasses, m1, has a mass of 6.0 kg and the other mass, m2, has a massof 4.0 kg. The force of the cord attached to m1 is, Tension ?

Explanation / Answer

Weight is pulling Mass 2 down by m2g. Throughthe use of the pully, mass 2 is pulling up on mass 1 throughthe pully by this same amount. Weight is pulling down on Mass1 by m1g. So add them together. T=m2g+m1g =g(m2+m1) = 9.8 * (4+6) = 9.8 * 10 = 98N

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