The drawing shows Robin Hood about to escape from a dangeroussituation. With one

Question

1. The drawing shows Robin Hood about to escape from a dangeroussituation. With one hand, he is gripping a rope that holds up a 195kg chandelier. When he cuts the rope where it is tied to the floor,the chandelier will fall, and he will be pulled up toward a balconyabove. Ignore the friction between the rope and the beam over whichit slides. Assume that Robin Hood’s mass is 77.0 kg
   1. Determine the acceleration with which Robin is pulledupward.
   2. Compute the tension in the rope.

I first found my ay ay=m2*g-s*m1*g/m1+m2 77kg*9.81-195kg*9.81/195+77 ay=4.25m/s2 Now once ive found this im not sure how to use it to fing thetension in the rope, can someone figure this out? I first found my ay ay=m2*g-s*m1*g/m1+m2 77kg*9.81-195kg*9.81/195+77 ay=4.25m/s2 Now once ive found this im not sure how to use it to fing thetension in the rope, can someone figure this out? Now once ive found this im not sure how to use it to fing thetension in the rope, can someone figure this out?

Explanation / Answer

Let's write a force equation Total force on the system of two masses equal to the differencebetween their weights. (m1+m2)a=m2g - m1g a=g(m2 - m1)/(m1+m2) a= 9.81( 195 - 77)/(195 + 77) a=4.26 m/s2 The tensions are Robin's side T2= m2(g + a) = 1083 N chandelier's side T2= m2(g - a) = 1083 N (as expected) That should do it. Please let me know if you have any questions.

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