A 1.00 µF capacitor is charged by being connected across a 8.0 V battery. It is

Question

A 1.00 µF capacitor is charged by being connected across a 8.0 V battery. It is then disconnected from the battery and connected across an uncharged 4.00 µF capacitor. Determine the resulting charge on each capacitor. 1 Your answer differs from the correct answer by 10% to 100%. µC (1.00 µF capacitor) 2 Your answer is within 10% of the correct value. This may be due to roundoff error, or you could have a mistake in your calculation. Carry out all intermediate results to at least four-digit accuracy to minimize roundoff error. µC (4.00 µF capacitor)

Explanation / Answer

Capacitor C1 is charged to 8.0 V, so that we get             Q = CV                 = 1.00 F * 8.0 V                  =8 C C1 is connected to C2 in parallel. We know that tocapacitors must have same voltage according to Kirchhoff voltagerule. We know that sum of Q1 and Q2 must equalto  8 C.                  V1 = V2                                   q1 / C1 = q2 / C2 By inspection we can see that the larger capacitor musthave the twice the charge as the smaller or 2/3 of the total           q1 = 8 C * 1/3 = 2.66C                q2= 8 C * 2/3 = 5.33C ( or workout with q2 = 8C - q1 andC1 = 1F so that C2 = 2F )

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