While standing at a crosswalk, you hear a frequency of 560 Hzfrom an approaching

Question

While standing at a crosswalk, you hear a frequency of 560 Hzfrom an approaching police car. After the police car passes, itsfrequency is 480 Hz. What is the speed of the police car? (speed ofsound= 340 m/s) A)13.1 m/s, B)17.4 m/s, C)21.1 m/s, D)26.2 m/s While standing at a crosswalk, you hear a frequency of 560 Hzfrom an approaching police car. After the police car passes, itsfrequency is 480 Hz. What is the speed of the police car? (speed ofsound= 340 m/s) A)13.1 m/s, B)17.4 m/s, C)21.1 m/s, D)26.2 m/s

Explanation / Answer

when the source is approaching the frequency heared is f' = (v + vo/v) * f -------------(1) f' = 560 Hz,v = 340 m/s and vo is speed ofobserver when the source is moving away the frequency heared is f'1 = (v - vo/v) * f --------------(2) f'1 = 480 Hz (1)/(2) (f'/f'1) = (v + vo/v - vo) or vo= v * [(f' - f'1/f + f'1)]

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