a vacuum filled parallel plate capacitor with a capacitance of20 mf is connected
ID: 1749261 • Letter: A
Question
a vacuum filled parallel plate capacitor with a capacitance of20 mf is connected to a 150 V source. A) what is the charge stored on the capacitor? B) what is the energy stored in the capacitor? C) if the battery is left connected to the capacitor and anylon dielectric K=4.3 is inserted between the plates, what is theenergy now stored, if different from before?Here is my problem. I don't understand the dielectricmess.... i am given two sets of formulas... part 1. c=kco v=vo/k E=Eo/k and U=u0/k
part 2 q=kqo v=vqo v=vo and u =kuo
so.. i don't know when to use which formula.. i think one setis for connected batteries and one isn't. any help would beappreciated. cheers a vacuum filled parallel plate capacitor with a capacitance of20 mf is connected to a 150 V source. A) what is the charge stored on the capacitor? B) what is the energy stored in the capacitor? C) if the battery is left connected to the capacitor and anylon dielectric K=4.3 is inserted between the plates, what is theenergy now stored, if different from before?
Here is my problem. I don't understand the dielectricmess.... i am given two sets of formulas... part 1. c=kco v=vo/k E=Eo/k and U=u0/k
part 2 q=kqo v=vqo v=vo and u =kuo
so.. i don't know when to use which formula.. i think one setis for connected batteries and one isn't. any help would beappreciated. cheers
Explanation / Answer
Charge stored on the capacitor Q = CV = 20 * 10 ^ -3 F * 150 V = 3 C (B). energy stored Uo = ( 1/ 2) C V ^ 2 = 225 J (C). If the battery is connected with capacitor thenenergy U = K Uo If the battery is disconnect with capacitor then energy U = U o / K where K = dielectric constant = 4.3Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.