QuestionDetails: The triangular loop of wire in the sketch carries a current ofI

Question

QuestionDetails: The triangular loop of wire in the sketch carries a current ofI = 2A in the direction indicated by arrows. Find the force exertedby the magnetic field on each side of the triangle. If the force isnot zero, specify its direction. The magnetic field is uniform, hasmagnitude B = 4 T, and is in the direction shown. Calcualte the netforce on the wire loop by considering the force on each segment ofwire. In solution provide all given values. Not a text problem.Require understanding of multiple concepts.`

Explanation / Answer

The force on any current is .    F = L I B sin   where      is the angle bewteen the Bfield and the current. . This also means that if the current and B field are parallel,the force is zero. . So... PQ:    force is zero .          QR: angle is 90 degrees, so     F = LIB = 1.6 * 2 *4 =   12.8 Newtons .                            direction of force on QR is "out of the screen", using the righthand rule .          RQ: angle between current and B field is   53 degrees so .                   F = 2.0 * 2 * 4 *sin53 = 12.8Newtons    direction? "into the screen", again using right hand rule. . total force?    12.8 out of screen +   12.8 into screen =   zero! . (hint:   net force on a current loopin a magnetic field is ALWAYS zero)

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