An RL series circuit is connected to an ac generator with amaximum EMF of 20 V.

Question

An RL series circuit is connected to an ac generator with amaximum EMF of 20 V. If the maximum potential difference across theresistor is 16 V, then the maximum potential difference across theinductor is: The answer is 12 V but I really don't know how to go aboutdoing this... An RL series circuit is connected to an ac generator with amaximum EMF of 20 V. If the maximum potential difference across theresistor is 16 V, then the maximum potential difference across theinductor is: The answer is 12 V but I really don't know how to go aboutdoing this...

Explanation / Answer

The same current is flowing through both R and L. The voltage across the resistor is in phase with that current, but the voltage across the inductor is 90 degrees out of phase with the current. The sum of the phasors representing the voltages across L and R are equal to the phasor representing the the supply voltage. If you sketch the phase diagram, you see that you can use pythagoras to solve: If voltage across inductor = v v

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