Steam at 100°C is added to ice at 0°C. (a) Find the amount of ice melted and the

Question

Steam at 100°C is added to ice at 0°C. (a) Find the amount of ice melted and the finaltemperature when the mass of steam is 12.0 g and the mass of ice is 51.0 g.
1 g
2°C

(b) Repeat this calculation, when the mass of steam as 1.20 g and the mass of ice is 51.0 g.
3 g
4°C (a) Find the amount of ice melted and the finaltemperature when the mass of steam is 12.0 g and the mass of ice is 51.0 g.
1 g
2°C

(b) Repeat this calculation, when the mass of steam as 1.20 g and the mass of ice is 51.0 g.
3 g
4°C

Explanation / Answer

Steam will give heat energy to ice.First ice will take latentheat (597 cal) and the come to water at zero degree.Now thetemperature of water will rise according to the heat available.Onthe other side Steam will first give its latent heat(540ccal) comesto water at 100 degree
heat loss by steam = mL + ms(t-100) = 0.012* 540 = 6.480+ 0.012*1*(100-t) heat gain by ice = mL + ms(t-0) = 0.051*597 + 0.051*1*(t-0) =30.447 + 0.051*(t-0)
here if steam will give energy till it comes at zero degreethen also it can give only 7.86 cal-kg energy but ice requireminimum 30.447 cal-kg energy to become water at zero degree. so icewill melt partially and finally some ice and some water will be atzero degree.
According to calorimetric law, Heat loss = heat gain =>6.480 + 0.012*1*(100 - 0) = m*597 => 7.68 = m*597 => m = 0.0128 kg => m = 12.8g
i.e only 12.8 gram ice will decay to water and rest 38.2gram ice will remain as it is.
similarly you can do calculation for other part.

Related Questions

Navigate

• Browse (All)
• Browse S
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.