Now assume that R1 = R2 = R3 = 2 ohms, and that Vbat = 12 V. Assume that the pot

Question

Now assume that R1 = R2 = R3 =2 ohms, and that Vbat = 12 V.

Assume that the potentialat the negative terminal of the battery is 0 volts. Write downthe

value of the potential(the voltage) at each point:

A. _____ B. ______ C._____ D. _____ E. _____ F. _____

h) Suppose the wire was cut at point C. Whatwould happen to the current flowing throughR1?______

If the wire was cut atpoint C, find these values:

V3(with wirecut) =_____________ V2(with wirecut) =_____________

i) Compared to thesituation before thewire was cut, would there be an increase, a decrease, or

no changein :

A. the amount of currentflowing through R1? ____________ Explain.

B. the amount of currentflowing through R3? ______________ Explain.

C. the amount of currentflowing through R2? _______________ Explain.

D. the amount of current flowingthrough the battery? ____________ Explain.

Explanation / Answer

the resistors R1 and R2 are in parallel therefore (1/R) = (1/R1) + (1/R2) = (1/2) + (1/2) = 1 ohms or R = 1 ohms the resistors R3 and R are in series therefore R' = R3 + R = 2 + 1 = 3 ohms the current flowing through the resistors R3 and R is Vbat = I * R' or I = (Vbat/R') = (12/3) = 4 ampere the current flowing through the resistors R1 and R2is I1 = (Vbat/R1) = (12/2) = 6 ampere and I2 =  (Vbat/R2) = (12/2) = 6 ampere value of the potential (the voltage) at each point: Va = I * R3 = 4 * 0 = 0 V Vb = I * R3 = 4 * 2 = 8 V Vc = Vb = 8 V Vd = I1 * R1 = Vbat = 12 V Ve = I2 * R2 = Vbat = 12 V h)the current flowing through R1 will become zero. When the wire was cut at point C then V3(with wirecut) = I * R3 =4 * 2 = 8 V and V2(with wirecut) = I2 * R2 =0 * 2 = 0 i)A.the amount of current flowing through R1 will becomezero.This is because the wire is cut at point C and the resistor isafter point C. B.the amount of current flowing through R3 will remainsame.This is because point C lies after the resistor R3. C.the amount of current flowing through R2 will remainsame.This is because the resistors R3 and R2 are stillconnected. D.the amount of current flowing through the battery willremain same.This is because the current will flow through theresistors R3 and R2.

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