Question
E) For region II describe the shape of the path.
Straightline through region
Parabolic curved upwards
Parabolic curved down
Straightangled up and to the right
Straightangled down and to the right
An electron initially moves in a horizontal direction and has akinetic energy of 2 x 10^3electron volts when it is in the position shown above. It passesthrough a uniform electric field between two oppositely chargedhorizontal plates (region I) and a field free region (region II)before eventually striking a screen at a distance of 0.08 meterfrom the edge of the plates. The plates are 0.04 meter long and areseparated from each other by a distance of 0.02 meter. Thepotential difference across the plates is 350 volts. Gravity is negligible a)Calculate the initial speed of the electron as itenters region I. b)Calculate the magnitude of the electric field Ebetween the plates, and indicate its direction on the diagramabove. c) Calculate the magnitude of the electric force Facting on the electron while it is in region I. d) On the diagram below, sketch the path of the electron in regionsI and II. For region I describe the shape of the path. Parabolic curved upwards Parabolic curved down Straightangled up and to the right Straightline through region Straightangled down and to the right E) For region II describe the shape of the path. Straightline through region Parabolic curved upwards Parabolic curved down Straightangled up and to the right Straightangled down and to the right
Explanation / Answer
a) KE = 1/2mv^2 2e3 =1/2(1.60e-19)v^2 (2e3) / ((1/2)(1.60e-19) =v^2 v = ? b) V = Ed 350 = E(.02) ? = E c) E = F / q Eq = F F = (answer for partb)(1.60e-19) F = ? d) parabolic curved upwards e) straight angled up and to the right d) parabolic curved upwards e) straight angled up and to the right
