1. A piano weighs 4500N.If the coefficient of sliding frictionbetween the piano

Question

1. A piano weighs 4500N.If the coefficient of sliding frictionbetween the piano and the floor is .25,what force Fapp is necessaryto move the piano at a CONSTANT speed. 2.If the applied force is not present in the previouspromblem,what is the piano's deceleration? 3. If two billard balls hit together on a level fictionlesspool tabel, and the combined momentum of the two balls before thecollision is 5 momentum units, what is the combined momentum of thetwo balls the collision? 1. A piano weighs 4500N.If the coefficient of sliding frictionbetween the piano and the floor is .25,what force Fapp is necessaryto move the piano at a CONSTANT speed. 2.If the applied force is not present in the previouspromblem,what is the piano's deceleration? 3. If two billard balls hit together on a level fictionlesspool tabel, and the combined momentum of the two balls before thecollision is 5 momentum units, what is the combined momentum of thetwo balls the collision?

Explanation / Answer

1) Moving at a constant speed means the net force is 0. Thereforethe applied force would equal the force of friction. Force of friction = FN      (FN is normalforce which equals the weight)                         = (4500) (0.25)                          =1125 N 2) Fg = mg m = Fg / g      = 4500 / 9.81      = 458.7 kg F = ma a = F / m    = 1125 / 458.7    = 2.45 m/s2 3) The momentum would be the same amount because it follows thelaw of conservation of momentum. 3) The momentum would be the same amount because it follows thelaw of conservation of momentum.

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