(a) Neglecting the mass of the rod, what is thesystem\'s kinetic energy when its

Question

(a) Neglecting the mass of the rod, what is thesystem's kinetic energy when its angular speed is 2.50 rad/s?
1 J

(b) Repeat the problem, assuming the mass of the rod is taken to be1.90 kg.
2 J A light rod 1.00 m in length rotates about an axis perpendicular toits length and passing through its center as in the figure below.Two particles of masses 4.00 kg and 3.00 kg are connected to theends of the rod. (a) Neglecting the mass of the rod, what is thesystem's kinetic energy when its angular speed is 2.50 rad/s? 1 J (b) Repeat the problem, assuming the mass of the rod is taken to be1.90 kg.

Explanation / Answer

L = 1.00 m, M = 4.00 kg, M' = 3.00 kg, = 2.50 rad/s a) K = M2(L/2)2/2 +M'2(L/2)2/2 = (M +M')2L2/8 = 5.47 J b) m = 1.90 kg. moment of inertia I = mL2/12 K' = K + I2/2 = 5.96 J

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