Two charges are located as shown in the figure. One charge ispositive and the ot
ID: 1745631 • Letter: T
Question
Two charges are located as shown in the figure. One charge ispositive and the other is negative; a. Find the magnitude of the electric field at P due to chargeq1. b. Find the magnitude of the electric field at P due to chargeq2. c. Find the magnitude of the net electric field at P due toboth charges. d. Find the direction of the net electric field at P due toboth charges. b=7MM Q2=-0.75coulombs c=8 MMExplanation / Answer
The Distance between the P to Q2 is : b2 + c2 = (0.007)2 + (0.008)2 = 0.0106 m (b) the magnitude of the electricfield at P due to charge q2 is : E = k q2 / r2 = 9 x 109 ( - 0.75 x 10-6 /(0.0106)2 ) = - 60.0 x 106 N / C Distance between P and Q1 is : a2 + c2 = (0.005)2 + (0.008)2 = 0.0094 m (a) the magnitude of the electricfield at P due to charge q1 is : E = k q1 / r2 = 9 x 109 ( 0.5 x 10-6/ (0.0094)2 ) = 50.92 x 106 N /C (c) Net charge is: 50.92 x 106 N/C - 60.0 x 106 N / C = - 9.08 x 106 N /C Hope this helps u! = 0.0094 m (a) the magnitude of the electricfield at P due to charge q1 is : E = k q1 / r2 = 9 x 109 ( 0.5 x 10-6/ (0.0094)2 ) = 50.92 x 106 N /C (c) Net charge is: 50.92 x 106 N/C - 60.0 x 106 N / C = - 9.08 x 106 N /C Hope this helps u! = 9 x 109 ( 0.5 x 10-6/ (0.0094)2 ) = 50.92 x 106 N /C (c) Net charge is: 50.92 x 106 N/C - 60.0 x 106 N / C = - 9.08 x 106 N /C Hope this helps u!Related Questions
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