An aluminum frying pan with a mass of 250 grams is heated on astove to 176 degre
ID: 1745494 • Letter: A
Question
An aluminum frying pan with a mass of 250 grams is heated on astove to 176 degrees Fahrenheit and then dropped into a sinkcontaining 750 grams of water at room temperature (20 degreesCelsius). Assuming that the tranfer of heat from one body to theother take place with no losses to the surrounding. a. What is the equilibrium temperature of the water andpen? b. How joules were lost by the frying pan? c. How many kilocalories were gained by the water? An aluminum frying pan with a mass of 250 grams is heated on astove to 176 degrees Fahrenheit and then dropped into a sinkcontaining 750 grams of water at room temperature (20 degreesCelsius). Assuming that the tranfer of heat from one body to theother take place with no losses to the surrounding. a. What is the equilibrium temperature of the water andpen? b. How joules were lost by the frying pan? c. How many kilocalories were gained by the water?Explanation / Answer
Given that the mass pan is M = 250 gm = 0.250 kg Initial temparature of the pan is T1 = 1760F = Mass of water is m = 750 g = 0.750 kg Initial temparature of water is T2 = 200C --------------------------------------------------------------------- (a) Let the final temparature of the system is T then Heat lossed by the hot body = heat gained by the cold body M*Ca*(T1 - T) = m*Cw*(T - T2) T = ( M*Ca*T1 + m*Cw* T2 ) / ( M*Ca + m*Cw ) = ---------- degrees where Cw = 4186J/kg.K is the specific heat for the water . Ca= 900 J/kg.K is the specific heat for the aluminum. (b) Heat lossed by the hotbody = M*Ca*(T1 - T) =--------- J (c) Heat lossed by the hot body = heatgained by the cold body = M*Ca*(T1 -T) =--------- J =--------- JRelated Questions
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