A bungee jumper jumps from a hot air balloon with an elasticcord attached to his

Question

A bungee jumper jumps from a hot air balloon with an elasticcord attached to his ankles. The unstretched length of the cord is25m, the student weighs 700N, and the balloon is 36m above thesurface of a river below. Assuming that Hooke's Law describes thecord, calculate the required force constant if the student is tostop safely 4m above the river. Please show all steps for full points. A bungee jumper jumps from a hot air balloon with an elasticcord attached to his ankles. The unstretched length of the cord is25m, the student weighs 700N, and the balloon is 36m above thesurface of a river below. Assuming that Hooke's Law describes thecord, calculate the required force constant if the student is tostop safely 4m above the river. Please show all steps for full points.

Explanation / Answer

before the jump, total energy is: E0 = mgh = 700N*36m = 25200J let the spring constant is k, when the student stop at 4mabove the river, the total energy is: E1 = PE0(gravity) +PE1(spring) = mg*4m +(1/2)k(25m-4m)2 for energy conservation, we have: E0=E1 =>mg*4m + (1/2)k(25m-4m)2 = 25200J k = (25200J - 700N*4m) *2 /(21m)2 = 101.59N/m I don't get the answer of 914N/m. for energy conservation, we have: E0=E1 =>mg*4m + (1/2)k(25m-4m)2 = 25200J k = (25200J - 700N*4m) *2 /(21m)2 = 101.59N/m I don't get the answer of 914N/m.

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