*****I keep getting 0.636m but it says that the answer iswrong, please help expl
ID: 1744681 • Letter: #
Question
*****I keep getting 0.636m but it says that the answer iswrong, please help explain why*** force of repulsion between A and B = ke(q2 / x2) force of repulsion between A and C = ke(2q2 / x12) equilibrium of A and C, the forces should be equal ke (q2 / x2)= ke (2q2 /x12) ( 1/ x2) = (2 /x12) 2 x2 = x12 x1 = (2) x = 1.414 * 0.45 m = 0.636 m the third charge must be placed at 0.636 m from the firstcharge force of repulsion between A and B = ke(q2 / x2) force of repulsion between A and C = ke(2q2 / x12) equilibrium of A and C, the forces should be equal ke (q2 / x2)= ke (2q2 /x12) ( 1/ x2) = (2 /x12) 2 x2 = x12 x1 = (2) x = 1.414 * 0.45 m = 0.636 m the third charge must be placed at 0.636 m from the firstcharge force of repulsion between A and C = ke(2q2 / x12) equilibrium of A and C, the forces should be equal ke (q2 / x2)= ke (2q2 /x12) ( 1/ x2) = (2 /x12) 2 x2 = x12 x1 = (2) x = 1.414 * 0.45 m = 0.636 m the third charge must be placed at 0.636 m from the firstcharge x1 = (2) x = 1.414 * 0.45 m = 0.636 m the third charge must be placed at 0.636 m from the firstchargeExplanation / Answer
force of repulsion between A and C = ke((2q)2 / x12) equilibrium of A and C, the forces should be equal ke (q2 / x2)= ke (4q2 /x12) ( 1/ x2) = (4 /x12) 4x2= x12 x1 = (4) x = 2 * 0.45 m = 0.9 m the third charge must be placed at 0.9 m from the firstcharge. Hope this helps u! x1 = (4) x = 2 * 0.45 m = 0.9 m the third charge must be placed at 0.9 m from the firstcharge. Hope this helps u!Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.