Two wires carry a currents of 5 A in opposite directions andare seperated by 10.

Question

Two wires carry a currents of 5 A in opposite directions andare seperated by 10.0 cm. Find the direction and magnitude of thenet magnetic field at the following locations: A. at a point midway between the wires B. at point P1, 10.0 cm to the right of the wire on theright C. at point P2, 20.0 cm to the left of the wire on theleft Two wires carry a currents of 5 A in opposite directions andare seperated by 10.0 cm. Find the direction and magnitude of thenet magnetic field at the following locations: A. at a point midway between the wires B. at point P1, 10.0 cm to the right of the wire on theright C. at point P2, 20.0 cm to the left of the wire on theleft

Explanation / Answer

        Given that thecurrents in the wires is I = 5A         The distancebetween the wires is d = 10 cm = 0.10 m    -----------------------------------------------------------------------------------   consider current in the right wire upwardand  left wire down wards .    (a) At midpoint           From the right hand rule the magnetic field directed same waydue to both wires                          Then net magnetic field is B = B1 + B2                                                                    = 0*I / 2(d/2) + 0*I / 2(d/2)                                                                     =20*I / 2d + 20*I / 2d                                                                     =40*I / 2d                                                                     =--------- T       wehere o =4*10-7 T.m/A            (b)  at point P1, 10.0 cm to the rightof the wire on the right           Thenthe distance between the second wire and the point is x = 20cm = 0.20m                                   Then net magnetic field is B = B1 - B2                                                                            = 0*I / 2d - 0*I / 2x                                                                              =--------- T   ( in ward)    (b)  at point P1, d = 20.0 cm tothe left of the wire on the right           Thenthe distance between the second wire and the point is x = 10cm = 0.20m                                   Then net magnetic field is B = B2 - B1                                                                            = 0*I / 2x - 0*I / 2d                                                                              =--------- T   (outward)                                                                                                = 0*I / 2d - 0*I / 2x                                                                              =--------- T   ( in ward)    (b)  at point P1, d = 20.0 cm tothe left of the wire on the right           Thenthe distance between the second wire and the point is x = 10cm = 0.20m                                   Then net magnetic field is B = B2 - B1                                                                            = 0*I / 2x - 0*I / 2d                                                                              =--------- T   (outward)                 Thenthe distance between the second wire and the point is x = 10cm = 0.20m                                   Then net magnetic field is B = B2 - B1                                                                            = 0*I / 2x - 0*I / 2d                                                                              =--------- T   (outward)                                                                               = 0*I / 2x - 0*I / 2d                                                                              =--------- T   (outward)                 

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