As a way of determining the inductance of a coil used in aresearch project, a st
ID: 1743994 • Letter: A
Question
As a way of determining the inductance of a coil used in aresearch project, a student first connects the coil to a10.0 V battery and measures a current of0.690 A. The student then connects thecoil to a 24.0 V (rms), 60.0 Hz generator and measures an rmscurrent of 0.570 A. What is the inductance?L = 1 mH
As a way of determining the inductance of a coil used in aresearch project, a student first connects the coil to a10.0 V battery and measures a current of0.690 A. The student then connects thecoil to a 24.0 V (rms), 60.0 Hz generator and measures an rmscurrent of 0.570 A. What is the inductance?
L = 1 mH
Explanation / Answer
Resistance ofcoil R = Vdc/ Idc = 10.0 /0.690 = 14.49 Impedance of thecoil Z = Vrms/ Irms = 24.0 /0.570 = 42.10 Z = R2 + XL2 42.102 = 14.492 + XL2 XL = (1772.41 - 209.96) = 39.53 Also inductivereactance XL = * L = 2 * f * L Inductance ofcoil L = 39.53/ 2 * 3.14 *60 = 0.105 H = 105 mH XL = (1772.41 - 209.96) = 39.53 Also inductivereactance XL = * L = 2 * f * L Inductance ofcoil L = 39.53/ 2 * 3.14 *60 = 0.105 H = 105 mHRelated Questions
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