How did cramster solve F as .5? In case you dont have the book, here is the ques

Question

How did cramster solve F as .5? In case you dont have the book, here is the question: If the magnitude of the magnetic force on a proton is F whenit is moving at 15 degrees with respect to the field, what isthe magnitude of the force (in terms of F) when this charge ismoving at 30 degrees with respect to the field. How did cramster solve F as .5? In case you dont have the book, here is the question: If the magnitude of the magnetic force on a proton is F whenit is moving at 15 degrees with respect to the field, what isthe magnitude of the force (in terms of F) when this charge ismoving at 30 degrees with respect to the field.

Explanation / Answer

Yes Sir, I don't have the book So let's do it - F1 = qvB sin(1) then qvB = F1/sin(1) F2 = [qvB] sin(2) F2 =[F1/sin(1)]sin(2) F2 = [F1](sin(2)/sin(1) ) F2 = [F1]( sin(30)/sin(15) ) F2 = 1.93 F1 Your Lordship, please let me know if you have anyquestions. F2 = [F1]( sin(30)/sin(15) ) F2 = 1.93 F1 Your Lordship, please let me know if you have anyquestions. Your Lordship, please let me know if you have anyquestions.

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