A 0.420 kg pendulum bobpasses through the lowest part of its path at a speedof 3
ID: 1743007 • Letter: A
Question
A 0.420 kg pendulum bobpasses through the lowest part of its path at a speedof 3.70 m/s. (a) What is the tension in the pendulum cable at this point if thependulum is 80.0 cm long?N
(b) When the pendulum reaches its highest point, what angle doesthe cable make with the vertical?
°
(c) What is the tension in the pendulum cable when the pendulumreaches its highest point?
N
(a) What is the tension in the pendulum cable at this point if thependulum is 80.0 cm long?
N
(b) When the pendulum reaches its highest point, what angle doesthe cable make with the vertical?
°
(c) What is the tension in the pendulum cable when the pendulumreaches its highest point?
N
Explanation / Answer
a) tension in the cable is due to weight andcentripetal force acting on the bob T = mg + 4^2. mr / t^2 m = mass of the pendulam t = time periof of pendulam b) if the angle made by the pedulam be = mgL(1-cos) = mv^2 / 2 L = length of pedulam v = velocity of bob at mean position from the above equation we can sovle for c) tension in the pendulum cable when the pendulum reaches itshighest point be T' T' = = mgcos + 4^2. mr / t^2 .Related Questions
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