For a hammer dropped on earth, the initial gravitational potentialenergy is 60.0

Question

For a hammer dropped on earth, the initial gravitational potentialenergy is 60.0J.
Part A: What would be the initial gravitational potential energy forthe hammer on the moon (where the acceleration due to gravity is1.67 m/s2) if it is releasefrom the same height in both places?
Part B: From what height (compared with the height on earth) would youhave to drop the hammer on Mars (where the acceleration due togravity is 3.70 m/s2 )to produce the same initialamount of potential energy that it had on earth?
Thanks
Part A: What would be the initial gravitational potential energy forthe hammer on the moon (where the acceleration due to gravity is1.67 m/s2) if it is releasefrom the same height in both places?
Part B: From what height (compared with the height on earth) would youhave to drop the hammer on Mars (where the acceleration due togravity is 3.70 m/s2 )to produce the same initialamount of potential energy that it had on earth?
Thanks

Explanation / Answer

Hi,     Part A              asinitial potential energy is proportional to the acceleration due togravity,                    Therefore the initial potentialenergy of the hammer on moon will be(60J)(1.67m/s2)/(9.8m/s2) = 10.22J     Part B                        Also forthe same potential energy, the height and the acceleration due togravity are inversely proportional.                So we can have hmars/hearth =gearth/gmars                Then height of the hammer on Mars is[(9.8m/s2)/(3.7m/s2)]hEarth = 2.65 hEarth           Hope thishelps you.

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