I am completely stumped, I\'ve tried Gauss Law but it doesn\'tseem to work. Can

Question

I am completely stumped, I've tried Gauss Law but it doesn'tseem to work. Can anyone help?

A square conducting slab of negligible thickness and with 4-m sidesis placed in an external uniform field E = (450 kN/C)i that is perpendicular to the faces of the slab.(a) Find the charge density on each face of the slab (b) A netcharge of 96C is placed on the slab. Find the new chargedensity on each face and the electric field near each face but farfrom the edges of the slab. I am completely stumped, I've tried Gauss Law but it doesn'tseem to work. Can anyone help?

A square conducting slab of negligible thickness and with 4-m sidesis placed in an external uniform field E = (450 kN/C)i that is perpendicular to the faces of the slab.(a) Find the charge density on each face of the slab (b) A netcharge of 96C is placed on the slab. Find the new chargedensity on each face and the electric field near each face but farfrom the edges of the slab.

Explanation / Answer

= q / 0 = E A q / A = E A = A / 0 Draw a Gaussian pillbox with the total area of the faces(perpendicular to E) equal 2 A then 2 A E = A / 0   the area of the faces considered is twice that related to thecharge density Then E = / (2 0) = 2 E 0 = 2 * 4.5 * 10E5 * 8.85 *10E-12 = 7.96 * E-6 C / m2 The density of the added charge is ' = q' / 16 =96 * 10E-6 / 16 = 6 * 10E-6 C / m2 The total charge density is now 13.96 * 10E-6 C /m2 The new electric field E = 13.96 * 10E-6 / (2 * 8.85 *10E-12) = 7.89 * 10E5 = 789 kN / C   The new electric field E = 13.96 * 10E-6 / (2 * 8.85 *10E-12) = 7.89 * 10E5 = 789 kN / C  

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