The normal force equals the magnitude of the gravitationalforce as a roller coas

Question

The normal force equals the magnitude of the gravitationalforce as a roller coaster car crosses the top of a 40-m-diameterloop the loop. What is the car's speed at the top? I don't know how i should do this problem. Im stuck with whatformula i should use and how i should work it out. The normal force equals the magnitude of the gravitationalforce as a roller coaster car crosses the top of a 40-m-diameterloop the loop. What is the car's speed at the top? I don't know how i should do this problem. Im stuck with whatformula i should use and how i should work it out.

Explanation / Answer

          At thetop of the loop the normal force is N = mg - mV2/R                                                                          From the given data N = mg   Then                                                                        mg =  mg - mV2 /R                                                                           V = 0 m/s           This is the velocity of the roller coaster at the top ofthe loop      

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