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Question

------------------------------------------------------------------------------------- I followed the Cramster's steps but gotthe wrong answer. Please help meout! Please help meout! A particle with a charge of 16 mu C experiences a force of 2.3 times 10 - 4 N when it moves at right angles to a magnetic field with a speed of 26 m / s. What force does this particle experience when it moves with a speed of 6.4 m / s at an angle of 23 degree relative to the magnetic field? Express your answer using two significant figures.

Explanation / Answer

Hi,     First of all let us calculate the magneticfield.     This is given bt the relation F = Bqv              or B =F/(qv)                    = (2.3*10-4N)/[(16*10-6C)(26m/s)]                    = 0.553T     Now when this charged particle enters into thefield with a speed 6.4m/s at an angle 23o relative tothe field, the force on th eparticle is F = Bqvsin                              = (0.553T)(16*10-6C)(6.4m/s)(sin23o)                             = 22.47*10-6N                              =2.25*10-5N Hope this helps you.

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