A 0.200kg object attached to a .900 m lomg string is spinningin a horizontal cir

Question

A 0.200kg object attached to a .900 m lomg string is spinningin a horizontal circle at a tangential speed of 12.0 m/s. A.) Find the Centripetal acceleration of the object B.)Find the Tension in the string C.)Assume the object in (A) is spinning in a vertical circle.What's the tension in the string at the top of the verticle circle?and (.D) at the bottom? A 0.200kg object attached to a .900 m lomg string is spinningin a horizontal circle at a tangential speed of 12.0 m/s. A.) Find the Centripetal acceleration of the object B.)Find the Tension in the string C.)Assume the object in (A) is spinning in a vertical circle.What's the tension in the string at the top of the verticle circle?and (.D) at the bottom?

Explanation / Answer

              Given that the mass of the object is m = 0.200 kg                Thelength of the string is L = 0.900 m                The tangential speed is U = 12.0 m/s ---------------------------------------------------------------------------      (a) The centripetal accelarationis ac = U2 /L                                                            = (12.0 m/s )2 / 0.900 m                                                             =160 m/s2        (b) The tention in the string is T =mac                                                        = ( 0.200 kg)( 160 m/s2)                                                      = 32 N       (c) At the bottom ofthe circle                              tention is Tb = mac + mg                                                   = --------- N            At the top of the circle the tention is                                               Tt = mac -mg                                                                = ------------- N         

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